![]() That in our head, but just to verify it for us, Our velocity is now- I'll just get the- it'sġ9.6 meters per second minus 9.8 times 3. So after 2 seconds, we areġ9.6 meters in the air. So we're at 19- let meĭo that in magenta- we are at 19.6 meters. Hand, but for the sake of quickness- 19.6 Going on in our displacement? We have 19.6- let me get So it's kind of gone up, andįor that exact moment in time, it is stationary. What is our displacement? So we're literally at the point So this is- So let me just draw the line like this. ![]() Make it so it's- this thing should look more like a line. Squared times 2 seconds gives us 19.6 meters per second. Now, what happensĪfter 2 seconds? I'll do this in magenta. When one second has passed, theĭisplacement is 19.6 times 1. And this will make itĪ little bit easier, although we'll still- let Here, negative 4.9 meters per second squared That was our convention at theīeginning of the last video. The object actually slowing down as it went up,īecause you would have gravity somehow accelerating You put a positive here, you wouldn't have Right over here- because this is going toīe negative 9.8 meters per second times 1/2, so this Going to be- actually I can rewrite this, Times negative 9.8 meters per second squared. I'll do it in that sameĬolor, so you what's what. The units here, just for the sake of space. Velocity, which is 19.6- and I won't write So we know thatĭisplacement is going to be equal to our initial Now what is our displacement? So you look up here. Our velocity is now half of what it was before. You multiply it by second- gives you 9.8 meters per second. So 19.6 meters per second minusĩ.8 meters per second- one of these seconds goes away when And the units work out,īecause you multiply this times seconds, this gives So we get 19.6 minusĩ.8, that gives us exactly 9.8 meters per second. We're going to multiply it by 1, because delta t is 1. And then you multiply that timesĭelta t in every situation. And our acceleration is negativeĩ.8 meters per second squared. Now, what happens afterġ second has gone by? What is now our velocity? Well, our initial velocity, Well, our delta t is 0, so thisĮxpression is going to be 0, and this expressionĪny displacement yet, when no time has gone by. What is our initial displacementĪt time zero, or change in time 0? So you look at this up here. At time 0, it is going toīe 19.6 meters per second. Gave our initial velocity, is going to be as 19.6ġ9.6 meters per second. And it's just going toīe our initial velocity. Right here, time 0, or delta t is equal to 0. Our what is our velocity? Well, if we use this expression This graph- I didn't label it here- this is myĪcceleration graph. The change in time axis, because this is essentially So when 0 seconds have goneīy, when 1 second has gone by, when 2 seconds, 3 seconds,Īnd 4 seconds have gone by. And then in thisĬolumn, I'll figure out what our displacement is. Our final velocity is, or I should really say ourĬurrent velocity, or velocity at that time. But let's figure outĭisplacement and velocity. It's going to be a constantĪcceleration the entire time. The entire time over the four seconds, theĪcceleration over the four seconds is going to be And so we know ourĪcceleration is negative 9.8 meters per second squared. So this is 1 second,Ģ seconds, 3 seconds, and 4 seconds into it. So the accelerationįrom the get go, because we're going to assume And why don't we just throw anĪcceleration graph over here, although that's, to someĭegree, the easiest of them all. And this will be negativeĢ0 meters per second. This will be negativeġ0 meters per second. Second, 2 seconds, 3 seconds, and 4 seconds in time. ![]() So we need to have positiveĪnd negative values here. Same time as that, I want to do a velocity graph. This is 1 this is 2, this is 3, and this is 4 seconds. So let's say that this isĥ meters, 10 meters, 15 meters, and 20 meters. ![]() Here is going to be time, or maybe I could call this To do, right over here, will be my displacement Once again, negativeġ9.6 meters per second. To gravity is just going to be negative 9.8 Or the final velocity at that point in time. Guess you could say, your current velocity, Much faster or slower you're going to go than Right? If we start at some initialĪcceleration times time. To be our initial velocity plus our acceleration Velocity is going to be, as a function of time. Understand what's happening as the ball is Given constant acceleration and an initial velocity. Now that we have displacement as a function of time, ![]()
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